Math, asked by santosh8031, 11 months ago

evaluate (999999)^2 in a suitable pattern ​

Answers

Answered by Anonymous
10

(999999)^2

= 999998000001

TO CALCULATE IT  COUNT THE NUMBER OF 9 AND IN THE SERIES PUT 5

THE 9 FIRST BUT 1 LESS THEN THE TOTAL NUMBER OF 9 IN THE SERIES THEN PUT ONLY ONE 8 THEN PUT 0 ONE LESS THAN THE NUMBER OF 9 IN THE SERIES AND AT LAST PUT ONLY A SINGLE 1.


santosh8031: please define
Anonymous: I HAVE TOLD YOU THE RULE NA
Anonymous: IT IS THE RULE OF ABACUS
Anonymous: AND VEDIC MATH ALSO
Anonymous: HOW IT COMES I TOLD YOU
santosh8031: thanks
Answered by eshaanvaswani
11
Hope it helps you.

Please mark it as brainliest.
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