Math, asked by eshanshaik26, 2 months ago

evaluate : 9ca + 6b ‐7c – 5abc, when a = 2, b = ⎼3 and c = 4

Answers

Answered by ppatel36132
1

Answer

evulate of 9ca+6b-7c–5abc,when a =2

Step-by-step explanation:

9ca

+6b

-7c

= +22ca =. 4

Answered by King1937
1

Answer:

If a = 2, b = -3 and c = 4 then the value of 9ca + 6b - 7c - 5abc is 146.

Step-by-step explanation:

Given : a = 2, b = -3 and c = 4

Solution : 9ca + 6b - 7c - 5abc

After putting the values, we get

9×(4×2) + 6×(-3) - 7×(4) - 5×[2×(-3)×4]

= 72 - 18 - 28 + 120

=146

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