Question

evaluate (a+1) (a-1) (a²+1)
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Answer 1

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We have been given the expression:-

(a+1)(a-1)(a²+1)

Using the identity 

a²−b²=(a+b)(a−b) :-

= (a²−1²)(a²+1)

=(a²−1)(a²+1)

Again using the identity 

a² - b² = (a+b)(a-b):-

= [(a²)²−1²]

= (a⁴−1)

So, it can be evaluated to (a⁴−1) !