Question

evaluate (a -1/a)(a+1/a)(a²+1/a²) for a= -2​

Answer 1

Answer:

Question 7 Let a be a non-zero real number. Evaluate the integral: ſo *cos(x) ox os() OA a2 e a²+1 COS + а e-X sin a²+1 +C where cis a constant. ОВ. 1 a²+1 e COS а + e a2+1 sin ^ +C where cis a constant. 1 e* cos a²+1 * cos(1) + 1 e-* sin a²+1 +C where c is a constant. OD а e a²+1 COS а + e-X sin a²+1 r()+c + C where cis a constant

Answer 2

(x+y)(x-y) = x²-y²

(a² - 1/a²)(a² +1/a²) = a⁴ - 1/a⁴

even power of a negative no. is positive no.

2⁴ -1/2⁴ = 16 - 1/16