Math, asked by mahesh7032, 11 months ago

evaluate a^2×a^3×a^-5​

Answers

Answered by vanshg28
2

Answer:

a^2 × a^3 × a^-5

= a^2+3-5

= a^0 = 1

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Answered by pranavbairy2
0

Answer:

= a^{2}×a^{3}×a^{-5}

= a^{5}×1/a^{5}

= 1

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