Math, asked by beautykumari0131, 4 months ago

Evaluate a^2 × a^3 × a^-5​

Answers

Answered by lisaagrawal2
0

Answer:

Step-by-step explanation:

a^2+3=a^5

=a^5×a^-5

=a^5-5

=a^0

=1

here two formulas used:

a^m×a^n=a^m+n(where m and n are numbers.)

a°=1

hence evaluated...

Answered by sreeraaga2506
1

Answer:

1

Step-by-step explanation:

a²×a³×a∧-5

So, it is in the form of a∧m × a∧n × a∧p = a∧m+n+p        

So, a²×a³×a∧-5 = a∧2+3+(-5)

                         = a∧2+3-5

                         = a∧5-5

                         = a∧0

Hence, a∧0 = 1

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