Math, asked by raoy1460, 2 months ago

evaluate
a 49+(-27)

b30+(_50)
c(_6)×(_8)
d(_40÷(_10)

Answers

Answered by vaishubh1707

0

Given:

a) 49+(-27)

b) 30+(-50)

c) (-6)×(-8)

d(-40)÷(-10)

To find:

Evaluate

Solution:

a) 49+(-27)

= 49-27

= 22

b) 30+(-50)

= 30-50

= -20

c) (-6)×(-8)

= 6× 8

= 48

d(-40)÷(-10)

= 40÷ 10

= 4

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