evaluate
a 49+(-27)
b30+(_50)
c(_6)×(_8)
d(_40÷(_10)
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Given:
a) 49+(-27)
b) 30+(-50)
c) (-6)×(-8)
d(-40)÷(-10)
To find:
Evaluate
Solution:
a) 49+(-27)
= 49-27
= 22
b) 30+(-50)
= 30-50
= -20
c) (-6)×(-8)
= 6× 8
= 48
d(-40)÷(-10)
= 40÷ 10
= 4
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