Evaluate:-
a){(7)⁰+(4)‐¹}×(2)²
b) {(3)²+(2)²–(4)²}÷(⅔)‐²
Answers
Answer:
(a) your answer is 5
Step-by-step explanation:
{7}^0+(4)-^1}×(2)^2
we know that,when the power is 0 on any number its value is 1 so
={1+1/4}×4
we also know that when the power is negative it will be reciprocal so we write 1/4
Firstly we solve bracket so
={1+1/4}×4
={5/4}×4
then we open bracket and solve them
=5/4×4
=5
It is your answer
Hope it will help you
THANK YOU
(b)your answer is -4/3
step by step solution:
{(3)^2+(2)^2-(4)^2}÷(2/3)^-2
firstly we solve bracket
={9+4-16}÷(2/3)^-2
we know that when the power is negative on any number it will be reciprocal here 2/3 reciprocal
={13-16}÷(3/2)^2
we open bracket
=-3÷9/4
we also know that when we remove the divide the signs change into multiply the number is reciprocal
=-3×4/9
=-4/3
It is your answer
Hope it will help you
THANK YOU