Question

Evaluate (a + b)2 by using method of multiplication of binomial with binomial . Based on your answer, find the value of squares of 51 and 111.

Answer 1

Answer:

( a² + b² + 2ab )

( 51 )² = 2601

( 101 )² = 10201

Step-by-step explanation:

To find--> Evaluate ( a + b )² by using multiplication of binomial with bionomial and calculate Value of squares of 51 and 111.

Solution---> We know that ,

( x + p ) ( x + q ) = x² + ( p + q )x + pq

Now,

( a + b )² = ( a + b ) ( a + b )

= a ( a + b ) + b ( a + b )

= a a + a b + b a + b b

( a + b )² = a² + 2 ab + b²

Now we find value of 51²,

51² = ( 50 + 1 )²

Applying ( a + b )² = a² + 2ab + b² , we get,

= ( 50 )² + ( 1 )² + 2 ( 50 ) ( 1 )

= 2500 + 1 + 100

= 2601

Now we calculate value of ( 101 )²

( 101 )² = ( 100 + 1 )²

Applying ( a + b )² = a² + b² + 2ab , we get,

= ( 100 )² + ( 1 )² + 2 ( 100 ) ( 1 )

= 10000 + 1 + 200

= 10201

#Answerwithquality

#BAL

Answer 2

Answer:

Step-by-step explanation:

To find--> Evaluate ( a + b )² by using multiplication of binomial with bionomial and calculate Value of squares of 51 and 111.

Solution---> We know that ,

( x + p ) ( x + q ) = x² + ( p + q )x + pq

Now,

( a + b )² = ( a + b ) ( a + b )

= a ( a + b ) + b ( a + b )

= a a + a b + b a + b b

( a + b )² = a² + 2 ab + b²

Now we find value of 51²,

51² = ( 50 + 1 )²

Applying ( a + b )² = a² + 2ab + b² , we get,

= ( 50 )² + ( 1 )² + 2 ( 50 ) ( 1 )

= 2500 + 1 + 100

= 2601

Now we calculate value of ( 101 )²

( 101 )² = ( 100 + 1 )²

Applying ( a + b )² = a² + b² + 2ab , we get,

= ( 100 )² + ( 1 )² + 2 ( 100 ) ( 1 )

= 10000 + 1 + 200

= 10201