Question

Evaluate :
(a + bc) (a - bc) (a² + b²c²)​

Answer 1

Answer:

(a+b+c)(a

2

+b

2

+c

2

−ab−bc−ac)

We know that(x+y+z)(x

2

+y

2

+z

2

−xy−yz−zx=x

3

+y

3

+z

3

−3xyz

Comparing both, we get

x=a,y=b and z=c

Then (a+b+c)[(a)

2

+(b)

2

+(c)

3

−(a)(b)−(b)(c)−(a)(c)]

=a

3

+b

3

+c

3

−3(a)(b)(c)

=a

3

+b

3

+c

3

−3abc

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