Question

Evaluate:
(a) x=h++%5 if h=5 initially​

Answer 1

Answer:

now value of a++ is a post increment so first it will use the same value i.e. a=10 and then do increment in ... int i=5,j=5,y,x; ... #include< stdio.h> int main() { int a=5; int b=++a*a++; printf("%d", b);

Answer 2

x=h++%5 if h=5 will evaluate to 0

$\large\mathsf\color{lightgreen}useful?\: \color{white}\longrightarrow\: \color{orange}brainliest!$