Math, asked by anshikapandey3103, 9 months ago

Evaluate a^x-y.a^y-z.a^z-x

Answers

Answered by mikecityno10
1

Answer:

1

Step-by-step explanation:

a^{x-y} . a^{y-z} . a^{z-x} \\

by rules of exponent

a^{x-y} - ^{y-z} = a^{x-z} \\a^{x-z} .  a^{z-x} = a^{x-z} - ^{z-x} \\a^0 = 1

since anything power zero = 1

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