Math, asked by ishaanpurohit010, 4 months ago

evaluate a2+ 3a – 88

Answers

Answered by aadityatiwari8
0

Answer:

a2 + 3a – 88 = a2 + 3a – 88 = a2 + 11a – 8a – 88 = a (a + 11) – 8 (a + 11) = (a – 8) (a + 11)

Answered by mittallakshay89
1

Answer:

a²+(11-8)a-88=0

a²+11a-8a-88=0

a(a+11)-8(a+11)=0

(a-8)(a+11)=0

Either a-8=0

a=8

OR a+11=0

a=-11

Step-by-step explanation:

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