Question

evaluate (a² + b²) (-a² + b²)​

Answer 1

Step-by-step explanation:

Given that:-

(a² + b²) (-a² + b²)

=>a²(-a²+b²)+b²(-a²+b²)

=>-a⁴+a²b²-b²a²+b⁴

=>-a⁴+a²b²-a²b²+b⁴

=>-a⁴+b⁴ or b⁴-a⁴

(a² + b²) (-a² + b²)=-a⁴+b⁴ or b⁴-a⁴

(or)

(a² + b²) (-a² + b²)

It can be written as (b²+a²)(b²-a²)

It is in the form of (x+y)(x-y)

Here, x=b² and y=a²

(x+y)(x-y)=x²-y²

(b²+a²)(b²-a²)=(b²)²-(a²)²

=>b⁴-a⁴

(a² + b²) (-a² + b²)=-a⁴+b⁴ or b⁴-a⁴

Answer 2

Answer:

(a² + b²) (- a² + b²)

= a² (- a² + b²) + b² (- a² + b²)

= $- a^{4}$ + a²b² - a²b² +$b^{4}$

= $- a^{4}$ + $b^{4}$

Hence, the answer is $- a^{4}$ + $b^{4}$

Hope it helps