Question

evaluate (a²b²-d²)² using the identity​

Answer 1

Step-by-step explanation:

Given : (a²−b²)(c²−d²)−4abcd

=a²c²−a²d²−b²c²+b²d²−2abcd−2abcd

=a²c²+b²d²−2abcd−a²d²+b²c²−2abcd

=(ac−bd)²−(ad−bc)²

=(ac−bd−ad+bc)(ac−bd+ad−bc) ....Since [p²−q²=(p−q)(p+q)]

Answer 2

Step-by-step explanation:

Using (a+b)

2

=a

2

+2ab+b

2

We can write (10.2)

2

=(10+0.2)

2

= (10)

2

+2(10)(0.2)+(0.2)

2

= 100+4+0.04

Hence the answer is 104.04