Evaluate after rationalizing the denominator of[ 25/√40-√80].it is given that √5=2.236 and √10=3.162.
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25/√40-√80
=25/2√10-4√5
=25/2(√10-2√5)
=25(√10+2√5)/2(√10-2√5)(√10+2√5)
=25(√10+2√5)/2(10-20)
=-25(√10+2√5)/20
=-5(√10+2√5)/4
=-5(3.162+2×2.236)/4
=-5(3.162+4.472)/4
=-5×7.634/4
=-5×1.9085
=-9.5425
=25/2√10-4√5
=25/2(√10-2√5)
=25(√10+2√5)/2(√10-2√5)(√10+2√5)
=25(√10+2√5)/2(10-20)
=-25(√10+2√5)/20
=-5(√10+2√5)/4
=-5(3.162+2×2.236)/4
=-5(3.162+4.472)/4
=-5×7.634/4
=-5×1.9085
=-9.5425
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Answer:
It is the answer ok tnx see you
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