Math, asked by vasundharameena45, 1 year ago

evaluate after simplification 3 pq (pq^2 - 2p^2q) for p =1, q =-1​

Answers

Answered by mysticd
12

Answer:

i)3pq(pq²-2p²q) = 3p²q³-6p³q²

ii)Value of 3pq(pq²-2p²q) = -9

Step-by-step explanation:

3pq(pq²-2p²q)

= 3pq×pq²-3pq×2p²q

= 3p²q³-6p³q²

If p=1,q=-1,

Value of 3pq(pq²-2p²q)

= 3p²q³-6p³q²

= 3×1²×(-1)³-6×1³×(-1)²

= 3×(-1)-6

= -3 - 6

= -9

Answered by Bpc1234
2

Answer:

Step-by-step explanation:

3pq(pq²-2p²q)

Putting p=1and q=-1

=3×1×-1(1×(-1)²-2(1)²-1)

=-3(1×1-(2×-1)

=-3(1+2)

=-3×3

=-9

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