evaluate after simplification 3 pq (pq^2 - 2p^2q) for p =1, q =-1
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Answered by
12
Answer:
i)3pq(pq²-2p²q) = 3p²q³-6p³q²
ii)Value of 3pq(pq²-2p²q) = -9
Step-by-step explanation:
3pq(pq²-2p²q)
= 3pq×pq²-3pq×2p²q
= 3p²q³-6p³q²
If p=1,q=-1,
Value of 3pq(pq²-2p²q)
= 3p²q³-6p³q²
= 3×1²×(-1)³-6×1³×(-1)²
= 3×(-1)-6
= -3 - 6
= -9
•••♪
Answered by
2
Answer:
Step-by-step explanation:
3pq(pq²-2p²q)
Putting p=1and q=-1
=3×1×-1(1×(-1)²-2(1)²-1)
=-3(1×1-(2×-1)
=-3(1+2)
=-3×3
=-9
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