Question

evaluate after simplification ABC (a ^2 +b^2 +c ^2) for a= 1,b=2, c = 3​

Answer 1

Answer:

Value of abc(a²+b²+c²) = 84

Step-by-step explanation:

Given a = 1 , b = 2 , c = 3

Value of abc(a²+b²+c²)

= 1×2×3(1²+2²+3²)

= 6(1+4+9)

= 6×14

= 84

Therefore,

Value of abc(a²+b²+c²) = 84

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