evaluate after simplification ABC (a ^2 +b^2 +c ^2) for a= 1,b=2, c = 3
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Answer:
Value of abc(a²+b²+c²) = 84
Step-by-step explanation:
Given a = 1 , b = 2 , c = 3
Value of abc(a²+b²+c²)
= 1×2×3(1²+2²+3²)
= 6(1+4+9)
= 6×14
= 84
Therefore,
Value of abc(a²+b²+c²) = 84
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