Question

Evaluate after simplification abc(a²+b²+c²)for a=1,b=2,c=3

Answer 1

Hey✨✨✨✨✨

Here is your answer,⬇⬇⬇⬇

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a = 1

b = 2

c = 3

Substitute these values ,

abc(a²+b²+c²) = (1)(2)(3) [(1)²+(2)²+(3)²]

= 6 [ 1 + 4 + 9 ]

= 6 x 14

= 84

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Hope it helps you!✔✔✔✔

Answer 2

a = 1 , b = 2 and c = 3





abc ( a² + b² + c² )




1 • 2 • 3 [ (1)² + (2)² + (3)² ]



6 ( 1 + 4 + 9 )



6 × 14




84