evaluate and plz answer
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Step-by-step explanation:
=√(2*√(2*√(2*...)
= (2*2½ * 2¼ * 2⅛*...)½
= 2½ * 2¼ * 2⅛ * 2¹/16*...
= 2^(1/2 + 1/4 + 1/8 + 1/16+....)
we know sum of GP = a/(1-r)
a = 1/2 , r = 1/4/1/2 = 1/2
=> 2^(1/2)/(1-1/2)
=> 2^(1/2 / 1/2)
=> 2
=> √2/√2/√2/√2...
=> 2^(1/2 - 1/4 + 1/8 - 1/16 + ....)
=> a = 1/2 , r = -1/4/1/2 = -1/2
=> 2^(1/2)/(1+1/2)
=> 2^(1/3)
=>(√2)^(√2)^(√2)^...
=> (2½)^(2½)^(2½)^....
=>(2)^(1/2*2)^(1/2*2)^(1/2*2)
=> = 2
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