Question

evaluate and show that {sin inverse (-4/5)= tan inverse (-4/3)}​

Answer 1

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HERE IS UR ANSWER

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Sin-¹(-4/5)=tan-¹(-4/3)

(Sin/cos)-¹=tan-¹

-4/3=-4/5

1/3sin-¹=1/5tan-¹

Answer 2

sin^-¹(-4/5)=A

-4/5=sinA

-5/4=cosecA

25/16=cosec²A

25/16=1+cot²A

cot²A=25/16. -1

cot²A=9/16

tan²A=16/9

tanA=±4/3

let -ve sign

tanA=-4/3

A=tan^-¹(-4/3)

sin^-¹(-4/5)=tan^-1(4/3)

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