Question

Evaluate another four different solution to the equation 4x+3y=12


please answer this question it is very urgent​

Answer 1

"

Four solutions -

(i) x = 0, y = 4

(ii) x = 3, y = 0

(iii) x = 6, y = - 4

(iv) x = -3, y = 8

Step-by-step explanation:

4x + 3y = 12

Solution no. 1 -

4x + 3y = 12

[let x = 0]

=> 4(0) + 3y = 12

=> 0 + 3y = 12

=> 3y = 12

=> y = 12/3

=> y = 4

Hence solution no. 1 =

x = 0, y = 4

solution no. 2 -

4x + 3y = 12

[let y = 0]

=> 4x + 3(0) = 12

=> 4x = 12

=> x = 12/4

=> x = 3

Hence solution no. 2 -

x = 3, y = 0

solution no. 3 -

4x + 3y = 12

[let x = 6]

=> 4(6) + 3y = 12

=> 24 + 3y = 12

=> 3y = 12-24

=> 3y = -12

=> y = -12/3

=> y = -4

Hence solution no. 3 =

x = 6, y = - 4

solution no. 4 -

4x + 3y = 12

[let y = 8]

= 4x + 3(8) = 12

=> 4x + 24 = 12

=> 4x = 12-24

=> 4x = -12

=> x = -12/4

=> x = -3

Hence solution no. 4 -

x = -3, y = 8

hope it helps.