Question

evaluate at x= -2 and y = 2 of ( x^2 + 2xy +y^2 )​

Answer 1

Answer:

answer is 0

use ( x + y )^2

so u will get

(-2+2)^2

0 ×0

=0

Answer 2

Answer:

x= -2, y =2 -------(given)

here, using formula

(a+b)² = a²+2ab+b²

:. (x+y)²= x²+2xy+y²

:. (-2+2)²= (-2)²+2×-2×2+(2)²

= 4-8+4

= 0