Question

evaluate ax-y.ay-z.az-x

Answer 1

The value of $ax-y.ay-z.az-x$ is equal to $x(a-1)-a(y^2+z^2)$.

Step-by-step explanation:

We have,

$ax-y.ay-z.az-x$

To find, the value of $ax-y.ay-z.az-x$ = ?

∴ $ax-y.ay-z.az-x$

= $ax-ay^2-az^2-x$

= $ax-x-ay^2-az^2$

= $x(a-1)-a(y^2+z^2)$

∴ The value of $ax-y.ay-z.az-x$ = $x(a-1)-a(y^2+z^2)$

Thus, the value of $ax-y.ay-z.az-x$ is equal to $x(a-1)-a(y^2+z^2)$.