Evaluate both the questions.
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✓ Answer with full explanation.
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sin^2(63)+sin^2(27)
we know that sin^2x+cos^2x=1
sin^2(63)+cos^2(63)=1
since sin^2(27)=cos^2(63)
same
cos^2(17)+cos^2(73)=1
sin^2(63)+sin^2(27)/cos^2(17)+cos^2(73) =1
sin25cos65+cos25sin65
sin a cos b+cos a sin b=sin(a+b)
therefore
sin25cos65+cos25sin65=sin(25+65)=sin90=1
we know that sin^2x+cos^2x=1
sin^2(63)+cos^2(63)=1
since sin^2(27)=cos^2(63)
same
cos^2(17)+cos^2(73)=1
sin^2(63)+sin^2(27)/cos^2(17)+cos^2(73) =1
sin25cos65+cos25sin65
sin a cos b+cos a sin b=sin(a+b)
therefore
sin25cos65+cos25sin65=sin(25+65)=sin90=1
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