evaluate by grouping a (b - c)2 - d (c-b)
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Answered by
0
Answer:
1 + a + ac + a2c
Solution:
1 + a + ac + a2c
= (1 + a) + (ac + a2c)
= (1 + a) + ac (1 + a)
= (1 + a) (1 + ac).
Step-by-step explanation:
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Answered by
1
Answer:
Hiiii..
This is your answer.
I hope it will help you.
Step-by-step explanation:
a(b-c)2-d(c-b)
(ab-ac)2-(dc-db)
2ab-2ac-dc+db
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