evaluate by proper identity (102)3
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Answered by
13
Hey friend, Here is your answer:-
(102)³ can be written as (100+2)³
We know that (a+b)³ = a³ + b³ + 3a²b + 3ab²
Here, a = 100 and, b = 2
= (100)³ + (2)³ + 3(100)²(2) + 3(100)(2)²
= 1000000 + 8 + 3(10000)(2) + 3(100)(4)
= 1000000 + 8 + 60000 + 1200
= 1061208
(102)³ = 1061208
Hope it helps...
Shruthi12345:
@ruhi5728, I hope it helps you!
Answered by
4
Answer:
(102)3=(100+2)3
=(100)3 +3(100)2+2(100)(2)2+(2)3
=1000000+3(10000)(2)+300(4+8)
=1000000+60000+1200+8
=1061208
Explanation:
hope this is helpfull...
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