Question

evaluate by simplication using laws of logarithms log216/log root 6​

Answer 1

Answer:

          6

Step-by-step explanation:

The only log law that you need is:

• log aᵇ  =  b log a

Using this:

$\displaystyle\frac{\log216}{\log\sqrt6}=\frac{\log6^3}{\log6^{1/2}}=\frac{3\log6}{\tfrac12\log6}=\frac{3}{1/2}=3\times2=6$