Math, asked by jack2572, 1 year ago

evaluate by suitable identity in 1.01 square​

Answers

Answered by vikasrajput8597
0

Answer:

(1.01)^2=(1+0.01)^2

=(1)^2+(0.01)^2+2*1*0.01

=1+ 0.0001+0.02

=1.0201

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