evaluate by using following suitable identity
999^3
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999³= (1000 - 1)³
By using , (a-b)³ = a³ - b³ - 3ab (a - b)
= (1000)³ - (1)³ - 3(1000) (1) (1000 -1)
= 1000 000 0001 - 3000 x 999
= 1000 000 000 - 1-2997000
= 997002999
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