evaluate by using suitable identity 104^3
Answers
Answered by
20
=104^3
=(100+4)^3
(a+b)^3=a^3+b^3+3ab(a+b)
=100^3+4^3+3(100)(4)(100+4)
=1000000+64+3(400)(104)
=1000064+1200(104)
=1000064+124800
=1124864
=(100+4)^3
(a+b)^3=a^3+b^3+3ab(a+b)
=100^3+4^3+3(100)(4)(100+4)
=1000000+64+3(400)(104)
=1000064+1200(104)
=1000064+124800
=1124864
Answered by
19
ANSWER
========
( 104 )³
=> ( 100 + 4 )³
{ We know , ( a + b )³ = a³ + b³ + 3ab ( a + b ) }
=> ( 100 )³ + ( 4 )³ + 3 ( 100 ) ( 4 ) ( 100 + 4 )
=> 1000000 + 64 + 1200 ( 100 + 4 )
=> 1000000 + 64 + 120000 + 4800
=> 1124864 ANS
=========================================
# BE BRAINLY
========
( 104 )³
=> ( 100 + 4 )³
{ We know , ( a + b )³ = a³ + b³ + 3ab ( a + b ) }
=> ( 100 )³ + ( 4 )³ + 3 ( 100 ) ( 4 ) ( 100 + 4 )
=> 1000000 + 64 + 1200 ( 100 + 4 )
=> 1000000 + 64 + 120000 + 4800
=> 1124864 ANS
=========================================
# BE BRAINLY
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