evaluate: (cos 13+ sin 77)sec 13+(sec 4+cos 76)cos 14
Answers
Answered by
4
Answer:
4
Step-by-step explanation:
(cos 13+ sin 77)sec 13+(sec 4+cos 76)cos 14
= [cos13 +sin(90-13)]sec13 + [Sec14+Cosec(90-14)]cos 14
= (2cos13)sec13 + (2sec14)cos14
= 2 + 2
= 4.
Similar questions
World Languages,
5 months ago
CBSE BOARD X,
5 months ago
English,
10 months ago
Physics,
10 months ago
Math,
1 year ago