Evaluate cos 195° for the answer above.
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Step-by-step explanation
first cos 15 = cos [45-30] =cos45cos30 +sin45sin30
=[1/√2][√3/2] + [1/2][1/√2] =[√3+1]/2√2
now cos 195 = cos[180 +15] = - cos 15 = -[√3+1]/2√2
formua used
cos[A-B] =cosAcosB +sinAsinB
COS[180+ A] = - cos A
mkrishnan:
AM I CORRECT
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