Question

evaluate Cos^2 20+ cos^2 70 + sin 48sec 92 + Cos 40 cosec50
Fast!! ​

Answer 1

welcome to the concept of trigonometry.

we know that

$\sin {}^{2} (x) + \cos {}^{2} (x) = 1$

and

$\sec(90 - x) = \csc( x)$

and

$\csc(90 - x ) = \sec(x)$

if in yr question sec 42 instead of sec92

then answer is 3.

otherwise if it's sec92

then, it is 2 + sin48 sec92.

I hope it help you❤️❤️

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sorry for late answer .....