Question

Evaluate cos(40°-theta)-sin(50°+theta)+(cos^2 40°+cos^2 50°)÷(sin^2 40°+sin^2 50°)=2​

Answer 1

Step-by-step explanation:

L.h.s=sin(90-(40-theta))-(sin(50+theta)+(cos^2 40+sin^2 40)+(cos^2 50+sin^2 50)

=sin(50+theta)-sin(50+theta)+(1)+(1)

=1+1=2

hence,proofed.