evaluate cos 48° cos 42° - sin 48° sin 42°
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Answers
Answered by
58
It is a formula of cos(A+B)
Cos(48+42)
Then, cos 90
= 0.
Cos(48+42)
Then, cos 90
= 0.
Answered by
121
We have to evaluate
cos 48° cos 42° - sin 48° sin 42°
We know that,
cos (A+B) = cos A cos B - sin A sin B
Here, A = 48° and B = 42°
Hence, with the help of the formula given above, we can write
cos 48° cos 42° - sin 48° sin 42° = cos (48° + 42°)
cos 48° cos 42° - sin 48° sin 42° = cos 90°
cos 48° cos 42° - sin 48° sin 42° = 0 (∵ cos 90°=0)
This is the required answer.
Hopefully it helps. Thank u.
cos 48° cos 42° - sin 48° sin 42°
We know that,
cos (A+B) = cos A cos B - sin A sin B
Here, A = 48° and B = 42°
Hence, with the help of the formula given above, we can write
cos 48° cos 42° - sin 48° sin 42° = cos (48° + 42°)
cos 48° cos 42° - sin 48° sin 42° = cos 90°
cos 48° cos 42° - sin 48° sin 42° = 0 (∵ cos 90°=0)
This is the required answer.
Hopefully it helps. Thank u.
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