Question

evaluate cos 48° - sin 42°​

Answer 1

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0

Step-by-step explanation:

$\cos(48) - \sin(42) \\ = \cos(90 - 42) - \sin(42) \\ = \sin(42) - \sin(42) = 0$

Answer 2

Answer:

0

Step-by-step explanation:

We know that

$\sin( {90}^{ \circ} - \theta) = \cos( \theta)$

So using this formula we get

$\sin( {42}^{ \circ} ) \\ = \sin( {90}^{ \circ} - {48}^{ \circ} ) \\ = \cos( {48}^{ \circ} ) \: \: \: \: \: \: \: \: \: \: \:$

So your question is nothing but

$\cos( {48}^{ \circ} ) - \sin( {42}^{ \circ} ) \\ = \cos( {48}^{ \circ} ) - \cos( {48}^{ \circ} ) \\ = 0 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:$