Math, asked by aammeeta, 1 year ago

Evaluate:
cos(50+°θ)–sin(40°-θ)

Answers

Answered by lekhahasa
2
cos(50°+θ)-sin(40-θ)=sin(90°-50°-θ)-sin(40°-θ)
                                 =sin(40°-θ)-sin(40°-θ)
                                 =0

adamsyakir: wrongg.
Answered by Anonymous
0
0.21985287 is the answer.....
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