Evaluate:
cos(50+°θ)–sin(40°-θ)
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2
cos(50°+θ)-sin(40-θ)=sin(90°-50°-θ)-sin(40°-θ)
=sin(40°-θ)-sin(40°-θ)
=0
=sin(40°-θ)-sin(40°-θ)
=0
adamsyakir:
wrongg.
Answered by
0
0.21985287 is the answer.....
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