Math, asked by mszarzoliani, 1 month ago

Evaluate:
cos 74°/sin 16°+sin 11°/cos 79°-cos 15°cosec 75°

Answers

Answered by Lokesh1429
2

Answer:

1

Step-by-step explanation:

cos 74°/sin 16°+sin 11°/cos 79°-cos 15°cosec 75°

cos 74°/cos (90-16)°+sin 11°/sin(90-79)°-cos 15°*1/sin 75°

cos 74°/cos 74°+sin 11°/sin11°-cos 15°*1/cos 15°

1+1-1=1

Answered by dipamcool2016
1

Hello Mate! Here is your answer:

= cos 74°/sin 16° + sin 11°/cos 79° - cos 15°cosec 75°

= cos (90-16)°/sin 16° + sin (90-11)°/cos 79° - cos 15°cosec (90-15)°

= sin 16°/sin 16° + cos 79°/cos 79° - cos 15°sec 15°

= 1+1+1    

= 3

I hope this helps.

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