Question

evaluate: cos 80 / sin 10 + cos 59 . cosec31

Answer 1

here is ur answer guys

Answer 2

Answer:

$\frac{cos80}{sin10}+cos59\cdot cosec31=2$

Step-by-step explanation:

$\frac{cos80}{sin10}+cos59\cdot cosec31$

$=\frac{cos(90-10)}{sin10}+cos59\cdot cosec(90-59)$

$=\frac{sin10}{sin10}+cos59\cdot sec59$

/*i)cos(90-A)=sinA

ii) cosec(90-A)=secA*/

$=1+ 1$

/* cosAsecA = 1 */

$=2$

Therefore,

$\frac{cos80}{sin10}+cos59\cdot cosec31=2$

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