Question

Evaluate Cos(logx)/x*dx

Answer 1

cos (logx)/x dx

let logx=t

then

1/x dx = dt

now

cos(t) dt

= sin(t)/t +c

putting t= logx

= sin(logx)/log(x)+ c. ans...

Answer 2

Answer:

sin[logx] + c

Step-by-step explanation:

INTEGRAL  Cos(logx)/x*dx

INTEGRAL  Cos(t)dt       here t = logx    dt = dx/x

=sin t + c

=sin[logx] + c

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