evaluate cos raise to 6 theta + sec raise to 6 theta if cos theta + sec theta = 2
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let theta =A
cosA+secA=2. ............eqn1
Cos 6A+ Sec 6A
=6(CosA+SecA)
=6(2).......from eqn 1
=12
hence, Cos6A+Sec6A=12
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