Math, asked by asha8952424, 3 months ago

Evaluate (COS0° + sin 45° + sin30°)(sin 90° - COS 45° + cos 60°).​

Answers

Answered by dhruvagarwa006
1

Answer:

(cos 0° + sin 45° + sin 30° )( sin 90°- cos 45° + cos 60°)

(1/ root 2 + 1/2 )(1- 1/ root 2 + 1/2)

(2+ root 2 / 2root 2 )(2 root 2 - 2 + root 2)

4 root 2 + 2 / 8

2( 2 root 2+ 1 )/4

(2 root + 1 ) /2

Answered by schnmoyal
1

Answer:

(cos0 +  \sin30)(sin90 - cos45 + cos60)

 = (1 +  \frac{1}{2} )(1 -  \frac{1}{ \sqrt{2} }  +  \frac{1}{2} )

 = ( \frac{3}{2} )(1 -  \frac{2}{ \sqrt{2} } )

 = ( \frac{3}{2} )(  \frac{3 \sqrt{2} }{ \sqrt{2} } )

  = \frac{3 \times 3 \sqrt{2} }{2 \times  \sqrt{2} }

  = \frac{9 \sqrt{2} }{2 \sqrt{2} }

  = \frac{9}{2}

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