Question

Evaluate cos2

θ tan2

θ +

tan2

θ sin2

θ in terms of tan θ.
plz tell me the answer its urgent​

Answer 1

plz. mark it as BRAINLIEST

Answer 2

$Given \: cos^{2} \theta tan^{2} \theta + tan^{2} \theta sin^{2} \theta$

$= tan^{2} \theta (cos^{2} \theta +sin^{2} \theta)$

$= tan^{2} \theta \times 1$

/* By Trigonometric Identity */

$\boxed{\pink{ cos^{2} \theta + sin^{2} \theta = 1 }}$

$= tan^{2} \theta$

Therefore.,

$\red{ cos^{2} \theta tan^{2} \theta + tan^{2} \theta sin^{2} \theta\: in \:terms \: of \: tan \:theta }$

$\green {= tan^{2} \theta}$

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