Question

evaluate !cos2x/√1+sin2x dx

Answer 1

let 1 + sin2x = t
differntiate to get
2* cos2x dx = dt

now cos2x dx = dt/2

put this in the integration given to get

(1/√t)*dt/2
solve it to get

2/2*√t + c

which equals √(1+sin2x) +c