Question

evaluate cos80°/sin10°+cos59°cosec31°​

Answer 1

Answer:

Refer To This Attachment ♣️✌️

Answer 2

$\frac{cos80}{sin10} + cos59cosec31 \\ = \frac{sin(90 - 80)}{sin10} + sin(90 - 59)cosec31 \\ ...(cosx = sin(90 - x)) \\ = \frac{sin10}{sin10} + sin31cosec31 \\ = 1 + 1 \: \: \: \: \: \: ...(sinx.cosecx = 1) \\ = 2$