Question

evaluate [cos90-○+sin90-○]^2+[sin90-○-cos90-○]^2​

Answer 1

Step-by-step explanation:

cos90°=0

sin90°=1

[0+1]^2 + [1-0]^2

=1^2 + 1^2

=1 + 1

=2

Answer 2

Step-by-step explanation:

cos90°=0

$in90=1

[cos90°-0+sin90°-0]^2+[sin 90°-0-cos90°-0]^2

=(0-0+1-0)^2+(1-0-0-0)^2

=1+1

=2

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