Question

Evaluate:
[(cosec^2 45 + sin30)(tan45 + sec^2 45)] / (sin^2 60 x cos^245)    {ans 20}

Answer 1

$cosec^{2}45$ = 2
sin30 = $\frac{1}{2}$
tan45 = 1
$sec^{2}45$ = 2
$sin^{2}60 = \frac{3}{4}$
$cos^{2}45= \frac{1}{2}$

now put the values...

= $\frac{(2 + \frac{1}{2})(1 + 2 ) }{ \frac{3}{4} * \frac{1}{2} }$ 

= $\frac{ \frac{(4+1)(3)}{2} }{ \frac{3}{8}}$

= $\frac{ \frac{15}{2} }{ \frac{3}{8} }$

= $\frac{15 * 8}{3 * 2}$

=20

Answer 2

Answer:

Step-by-step explanation:

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