Question

evaluate cosec^2 (90-@) - tan2@ / 4(cos2 40 + cos2 50) - 2tan2 30sec2 52sin2 38 / 3(cosec2 75- tan2 15) + sec (90 - @) sin@ + sin (40 + @) - cos (50 - @) cosec1 / sec89

Answer 1

Answer:

Solution:

________________________

We are using following :

i)

ii) We know the Trigonometric identity:

Sec²A - tan²A = 1

iii)

iv) sin²A + cos²A = 1

v) tan30° = 1/√3

vi) sec52° = sec(90-38) =cosec38°

vii ) cosecAsinA = 1

viii)cosec70= cosec(90-20)

= sec20°

ix ) cosec²A - cot²A = 1

_______________________

Now ,

LHS =

=

=

=

= $\frac{(3-4)}{6}$

= $\frac{-1}{6}$

Therefore,

= -1/6

hope it helps u

please mark as brainliast ansewer

Step-by-step explanation: