Math, asked by arinath19, 4 months ago

evaluate: cosec^2(90-theta)-tan^2theta/4[cos^248+cos^242] - 2tan^2 30.sec^52.sin^38/cosec^2 70-tan^2 20

Answers

Answered by satishkumar43
0

Answer:

here in this trigonometric functions equal to are not there so we can't find theta and there fore we can't evaluate answer

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